实验三课后作业

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项目二本月有几天

#include <iostream>using namespace std;int main(){int y,m;cout<<"请输入年份："<<endl;cin>>y; cout<<"请输入月份："<<endl;cin>>m;if((y%4==0&&y%100!=0)||(y%400==0)){if(m==1||m==3||m==5||m==7||m==8||m==10||m==12)cout<<"您查询的月份有31天\n";else if(m==4||m==6||m==9||m==11)cout<<"您查询的月份有30天\n";else if(m==2) cout<<"您查询的月份有28天";else cout<<"输入错误\n"; } else switch(m){ case 1: cout<<"您查询的月份有31天\n"; break; case 2: cout<<"您查询的月份有29天\n";break; case 3: cout<<"您查询的月份有31天\n";break; case 4: cout<<"您查询的月份有30天\n"; break; case 5: cout<<"您查询的月份有31天\n"; break; case 6: cout<<"您查询的月份有30天\n"; break; case 7: cout<<"您查询的月份有31天\n"; break; case 8: cout<<"您查询的月份有31天\n"; break; case 9: cout<<"您查询的月份有30天\n"; break; case 10: cout<<"您查询的月份有31天\n";break; case 11: cout<<"您查询的月份有30天\n"; break;  case 12: cout<<"您查询的月份有31天\n"; break; default: cout<<"输入错误\n"; break; }return 0; }

项目三定期存款计算器

#include <iostream>using namespace std;int main() {double sMoney,interest,sum;int n; cout<<"请输入要存的金额：\n";cin>>sMoney; cout<<"存款期限\n";cout<<"1.3个月\n";cout<<"2.6个月\n";cout<<"3.一年\n";cout<<"4.二年\n";cout<<"5.三年\n";cout<<"6.五年\n";cin>>n;switch(n) { case 1: interest=sMoney*0.25*0.031,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break; case 2: interest=sMoney*0.5*0.033,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break;case 3: interest=sMoney*1*0.035,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break;case 4: interest=sMoney*2*0.044,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break;case 5: interest=sMoney*3*0.05,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break; case 6: interest=sMoney*5*0.055,sum=sMoney+interest,cout<<"您的到期利息为"<<interest<<"元，本息合计共"<<sum<<"元。"; break; }cout<<"感谢您的使用, 欢迎下次光临!\n";return 0;}

项目四多分数段函数求值

#include <cmath>#include <iostream>   using namespace std;int main(){double x,y;int n;while(cin>>x){if(x<2) n=1;else if(x>=2&&x<6) n=2;else if(x>=6&&x<10) n=3;else n=4;switch(n){case 1:y=x;break;case 2:y=x*x+1;break;case 3:y=sqrt(x=1);break;case 4:y=1/(x+1);break;}cout<<y<<endl;}return 0;}

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