【JLOI2013】T1、T2、T3 Bzoj3190~3192

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T1: 赛车 Bzoj3190

画个s-t图像,写个水平可见直线,注意只维护x>=0的部分。

#include<cstdio>#include<cstring>#include<iostream>#include<cstdlib>#include<algorithm>#include<stack>using namespace std;const int maxn = 10005;int n;struct line{int a,b;int id;}L[maxn];bool cmp(line x,line y){return x.a<y.a || (x.a==y.a && x.b>y.b);}bool ans[maxn];int Ans[maxn];stack<double>sta1;stack<line>sta2;double cross(line x,line y){return (y.b-x.b)*1.0/(x.a-y.a);}int main(){freopen("race.in","r",stdin);freopen("race.out","w",stdout);scanf("%d",&n);int maxb=-100000;for(int i=1;i<=n;i++){scanf("%d",&L[i].b);L[i].id=i;maxb=max(maxb,L[i].b);}for(int i=1;i<=n;i++){scanf("%d",&L[i].a);if(L[i].b==maxb)ans[i]=1;}sort(L+1,L+1+n,cmp);sta1.push(0);sta2.push(L[1]);for(int i=2;i<=n;i++){if(L[i].a==L[i-1].a)continue;while(!sta2.empty() && cross(L[i],sta2.top())<sta1.top())sta1.pop(),sta2.pop();if(!sta2.empty())sta1.push(cross(L[i],sta2.top()));else sta1.push(0);sta2.push(L[i]);}int cnt=0;while(!sta2.empty()){ans[sta2.top().id]=1;sta2.pop();}for(int i=1;i<=n;i++)if(L[i].a==L[i-1].a && L[i].b==L[i-1].b)ans[L[i].id]=ans[L[i-1].id];int t=0;for(int i=1;i<=n;i++)if(ans[i])Ans[++t]=i;printf("%d\n",t);for(int i=1;i<t;i++)printf("%d ",Ans[i]);printf("%d\n",Ans[t]);}/*41 1 0 015 16 10 20*/


T2:卡牌游戏Bzoj3191

是谁不重要,重要的是和庄家的距离,用f[i][j]表示还剩i个人时,从庄家开始数第j个人胜率,枚举所有状态,f[i][j]由f[i-1][*]转移即可

#include<bits/stdc++.h>using namespace std;#define MADOKA mainconst int maxn = 55;int a[maxn];int n,m;double f[maxn][maxn];int MADOKA(){scanf("%d%d",&n,&m);for(int i=1;i<=m;i++)scanf("%d",&a[i]);f[1][1]=1;for(int i=2;i<=n;i++)for(int j=1;j<=i;j++)for(int k=1;k<=m;k++){int tmp=a[k]%i;if(tmp==0)tmp=i;if(tmp==j)continue;if(tmp>j)tmp=i+j-tmp;else tmp=j-tmp;f[i][j]+=f[i-1][tmp]*1.0/m;}for(int i=1;i<n;i++)printf("%.2lf%% ",f[n][i]*100.0);printf("%.2lf%%\n",f[n][n]*100.0);}


T3:删除物品Bzoj3192

如图:


#include<bits/stdc++.h>using namespace std;const int maxn = 100005;#define LL long longstruct node{int k,p;}a[maxn];int n1,n2,n;LL ans=0;bool cmp(node a,node b){return a.k>b.k;}LL c[maxn];#define lowbit(x) (x&-x)void add(int pos,int d){ for(inti=pos;i<=n;i+=lowbit(i))c[i]+=d; }LL query(int pos){ LL ret=0;for(int i=pos;i>0;i-=lowbit(i))ret+=c[i];return ret; }LL query(int pos1,int pos2){ int ret; if(pos1>pos2)ret=0; else ret=query(pos2)-query(pos1-1); return ret; }int main(){freopen("remove.in","r",stdin);freopen("remove.out","w",stdout);scanf("%d%d",&n1,&n2);n=n1+n2;for(int i=1;i<=n1;i++){scanf("%d",&a[i].k);a[i].p=n1-i+1;}for(int i=n1+1;i<=n;i++){scanf("%d",&a[i].k);a[i].p=i;}sort(a+1,a+1+n,cmp);LL P=n1;for(int i=1;i<=n;i++){int x=a[i].p;if(x < P)ans+=(LL)P-x-query(x+1,P),P=x;else if(x>P) ans+=(LL)x-1-P-query(P+1,x-1),P=x-1;add(x,1);}cout<<ans<<endl;}



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