角色类游戏,析构函数

来源:互联网 发布:linux vi退出命令 编辑:程序博客网 时间:2024/05/20 15:10
#include <iostream>using namespace std;class Role{public:        Role(string Name,int Blood)        {            name=Name;            blood=Blood;        }        void show()        {            cout<<name<<"剩余"<<blood<<"滴血,";            if(blood>0)                cout<<"it is alived"<<endl;            else                cout<<"it is dead"<<endl;        }        ~Role()        {            cout<<name<<"退出江湖..."<<endl;        }private:    string name;    int blood;    bool life;};int main(){    Role mary("Mary",4);    Role jack("Jack",0);    mary.show();    jack.show();    return 0;}

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