Android 拷贝Asset目录下文件或者文件夹

来源：互联网发布：java开发语言编辑：程序博客网时间：2024/05/22 07:08

项目中需要拷贝Asset目录下的所有文件，因为Asset目录是只读的，操作起来不是很方便，上网搜了一些方法并不是很有效，记录一下最后的解决方案：

//path - asset下文件（夹）名称  destinationPath - 目的路径`private void copyAssetFile(String path,String destinationPath) {    AssetManager assetManager = mContext.getAssets();    String assets[] = null;    try {        Log.i("tag", "copyFileOrDir() "+path);        assets = assetManager.list(path);        if (assets.length == 0) {            copyFile(path,destinationPath);        } else {            String fullPath =  destinationPath + path;            Log.i("tag", "path="+fullPath);            File dir = new File(fullPath);            if (!dir.exists() && !path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit"))                if (!dir.mkdirs())                    Log.i("tag", "could not create dir "+fullPath);            for (int i = 0; i < assets.length; ++i) {                String p;                if (path.equals(""))                    p = "";                else                    p = path + "/";    if (!path.startsWith("images") && !path.startsWith("sounds") && !path.startsWith("webkit"))                    copyAssetFileOrDir( p + assets[i],destinationPath);            }        }    } catch (IOException ex) {        Log.e("tag", "I/O Exception", ex);    }}``private void copyFile(String filename,String destinationPath) {    AssetManager assetManager = mContext.getAssets();    InputStream in = null;    OutputStream out = null;    String newFileName = null;    try {        Log.i("tag", "copyFile() "+filename);        in = assetManager.open(filename);        newFileName = destinationPath + filename;        out = new FileOutputStream(newFileName);        byte[] buffer = new byte[1024];        int read;        while ((read = in.read(buffer)) != -1) {            out.write(buffer, 0, read);        }        in.close();        in = null;        out.flush();        out.close();        out = null;    } catch (Exception e) {        Log.e("tag", "Exception in copyFile() of "+newFileName);        Log.e("tag", "Exception in copyFile() "+e.toString());    }}`

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