LeetCode 58. Length of Last Word

Given a string s consists of upper/lower-case alphabets and empty space characters' ', return the length of last word in the string.

If the last word does not exist, return 0.

Note: A word is defined as a character sequence consists of non-space characters only.

For example,
Given s = "Hello World",
return 5.

Two pointers easy version.

#include <string>#include <iostream>using namespace std;int lengthOfLastWord(string s) {    if(s.size() == 0) return 0;    int i = s.size() - 1;    while(i >= 0 && s[i] == ' ') {        i--;    }    int j = i;    while(j >= 0 && s[j] != ' ') {        j--;    }    return i - j;}int main(void) {    int len = lengthOfLastWord("a dc ");    cout << len << endl;}