leetcode ——29——Divide Two Integers
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Divide two integers without using multiplication, division and mod operator.
If it is overflow, return MAX_INT.
class Solution {public: int divide(int dividend, int divisor) { int sign = (dividend < 0) ^ (divisor < 0) ? - 1 : 1; long long res = 0, m = abs((long long)dividend), n = abs((long long)divisor); while(m >= n) { long long t = n, i = 1; while(t << 1 < m) { t <<= 1; i <<= 1; } m -= t; res += i; } if(sign < 0) res = -res; return res > INT_MAX ? INT_MAX : res; }}; 0 0
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