doGet和doPost乱码

来源：互联网发布：网络动漫黑名单解禁编辑：程序博客网时间：2024/05/16 05:28

doGet和doPost,doPost可以用doGet代码解决反之不能

public class GetPostMethod extends HttpServlet {    public void doGet(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        String username = request.getParameter("username");        username = new String(username.getBytes("iso-8859-1"), "utf-8");        System.out.println(username);    }    public void doPost(HttpServletRequest request, HttpServletResponse response)            throws ServletException, IOException {        request.setCharacterEncoding("utf-8");        String username = request.getParameter("username");        System.out.println(username);    }}

html页面

    <form action="/d_response/getpost" method="get">        <input type="text" name="username">        <input type="submit" value="提交">    </form>    <form action="/d_response/getpost" method="post">        <input type="text" name="username">        <input type="submit" value="提交">    </form>

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