[Interactive Python] Rock-paper-scissors-lizard-Spock 游戏 Mini-project #1

很高兴今天早晨独立实现RPSLS小游戏，分享至此！

“RPSLS”游戏全称为Rock-paper-scissors-lizard-Spock，剪刀-石头-布的升级版。为了降低平手概率，增添了2个角色：Spock和蜥蜴君。

游戏规则是：每个都能赢2个输2个并与自己持平。在这里，剪刀能剪纸和蜥蜴；纸可以包住石头，驳斥Spock；石头击烂蜥蜴和剪刀；蜥蜴可以毒害Spock，吃纸；最后，Spock可以砸碎剪刀，使石头蒸发。

Mini-project描述：https://www.coursera.org/learn/interactive-python-1/supplement/ijRP5/mini-project-description

收获：

原来编程，最重要的是能静下心来分析。如果感到棘手，可以休息会儿，补足精力再战，就真的可以克服呢！

这是我的解答，若有更好的建议，欢迎指点~~

#RPSLSimport randomdef name_to_number(name):if name == 'rock':return 0elif name == 'Spock':return 1elif name == 'paper':return 2elif name == 'lizard':return 3elif name == 'scissors':return 4else:print('Please input name among:"rock", "paper", "scissors", "lizard", or "Spock".')def number_to_name(number):if number in range(0,5):if number == 0:return 'rock'elif number == 1:return 'Spock'elif number == 2:return 'paper'elif number == 3:return 'lizard'elif number == 4:return 'scissors'else:print('Please input number n the range 0 to 4.')def rpsls(player_choice):print()print('Player chooses',player_choice)player_number = name_to_number(player_choice)comp_number = random.randrange(0,5)comp_choice = number_to_name(comp_number)print('Computer chooses',comp_choice)if player_number - comp_number in range(-4,-2) or range(1,3):print('Player wins!')elif player_number - comp_number in range(-2,0) or range(3,5):print('Computer wins!')elif player_number - comp_number == 0:print('Tie!')else:print('Error!')print('"Rock-paper-scissors-lizard-Spock" game Start!')rpsls("rock")rpsls("Spock")rpsls("paper")rpsls("lizard")rpsls("scissors")