HUST 1010 The Minimum Length

题目链接：HUST1010

1010 - The Minimum Length

Time Limit: 1s Memory Limit: 128MB

Submissions: 1672 Solved: 611 

DESCRIPTION

There is a string A. The length of A is less than 1,000,000. I rewrite it again and again. Then I got a new string: AAAAAA...... Now I cut it from two different position and get a new string B. Then, give you the string B, can you tell me the length of the shortest possible string A. For example, A="abcdefg". I got abcdefgabcdefgabcdefgabcdefg.... Then I cut the red part: efgabcdefgabcde as string B. From B, you should find out the shortest A.

INPUT

Multiply Test Cases. For each line there is a string B which contains only lowercase and uppercase charactors. The length of B is no more than 1,000,000.

OUTPUT

For each line, output an integer, as described above.

SAMPLE INPUT

bcabcabefgabcdefgabcde

SAMPLE OUTPUT

37

题意：给出一个字符串，问最小的循环节是多少。

题目分析：next求循环节。

////  main.cpp//  HUST1010////  Created by teddywang on 16/4/26.//  Copyright © 2016年 teddywang. All rights reserved.//#include <iostream>#include<cstdio>#include<cstring>#include<algorithm>using namespace std;char s[1000010];int nexts[1000010],len;void getnext(){    int i=0,j=-1;    nexts[0]=-1;    while(i<len)    {        if(s[i]==s[j]||j==-1)        {            nexts[++i]=++j;        }        else j=nexts[j];    }}int main(){    while(~scanf("%s",s))    {        len=strlen(s);        getnext();        int l=len-nexts[len];        cout<<l<<endl;    }}