如何取得中的存储过程的返回值

来源:互联网 发布:lua 5.3 windows 安装 编辑:程序博客网 时间:2024/06/05 20:35
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声明存储过程
CREATEPROCEDUREsp_results_demo@InParmIntInt,@OutParmIntOUTPUT
AS
BEGIN
SELECT1,2,3,4
SELECTuid,id
FROMsysobjects
WHEREtype='U'

SELECT@OutParmInt=69

Return16
END
用于返回每个返回值时用PowerScrip如下:
LonglReturn,lPram1,lPram2,lResult1,lResult2,lResult3,lResult4,lResult5,lResult6

DECLAREresults_demoPROCEDUREFOR
@returnValue=sp_results_demo
@InParmInt=:lPram1,
@OutParmInt=:lPram2OUTPUTusingsqlca;

executeresults_demo;

DoWhileSQLCA.SQLCode=0
Fetchresults_demoINTO:lResult1,:lResult2,:lResult3,:lResult4;
Loop

Fetchresults_demoINTO:lResult5,:lResult6;

DoWhilesqlca.sqlcode=0
Fetchresults_demoInto:lResult5,:lResult6;
Loop

Fetchresults_demoInto:lReturn,:lPram2;

Closeresults_demo;


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