UVa 401 Palindromes

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本题展现了JAVA字符处理的强大能力

import java.util.Scanner;public class Main {  public static void main(String[] args) {    Scanner cin = new Scanner(System.in);    while (cin.hasNextLine()) {      String s = cin.nextLine();      String ss = new String(s);      System.out.print(s);      String s1 = new String(new StringBuffer(s).reverse().toString());      boolean flag = true, flag1 = true;      for (int i = 0; i < s.length(); i++) {        if (s1.charAt(i) != s.charAt(i)) {          flag = false;          break;        }      }      char[] a = s.toCharArray();      String old = "ABCDEFGHIJKLMNOPQRSTUVWXYZ12345678";      String now = "A   3  HIL JM O   2TUVWXY 1SE Z  8";      for (int i = 0; i < a.length; i++) {        char ch = now.charAt(old.indexOf(a[i]));        if (ch != ' ') {          a[i] = ch;        }else {          flag1 = false;          break;        }      }      if (flag1) {        s = String.valueOf(a);        String s2 = new String(new StringBuffer(s).reverse().toString());        for (int i = 0; i < ss.length(); i++) {          if (s2.charAt(i) != ss.charAt(i)) {            flag1 = false;            break;          }        }      }      if (!flag && !flag1) System.out.println(" -- is not a palindrome.");      if (flag && !flag1) System.out.println(" -- is a regular palindrome.");      if (!flag && flag1) System.out.println(" -- is a mirrored string.");      if (flag && flag1) System.out.println(" -- is a mirrored palindrome.");      System.out.print('\n');    }  }}

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