leetcode-74. Search a 2D Matrix

74. Search a 2D Matrix

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Total Accepted: 77864 Total Submissions: 230283 Difficulty: Medium

Write an efficient algorithm that searches for a value in an m x n matrix. This matrix has the following properties:

Integers in each row are sorted from left to right.

The first integer of each row is greater than the last integer of the previous row.

For example,

Consider the following matrix:

[  [1, 3, 5, 7], 

   [10, 11, 16, 20],  

   [23, 30, 34, 50]]

Given target = 3, return true.

//二分查找非递归 bool Binary_Search(vector<int> num, int len,int target){int low=0,hight=len-1,mid;while(low<=hight){mid=(low+hight)/2;if(num[mid]==target)return true;else if(num[mid]>target)hight=mid-1;elselow=mid+1;}return false;}bool searchMatrix(vector<vector<int> >& matrix, int target) {bool isOk=false;    for(int i=0;i<matrix.size();i++){    if(Binary_Search(matrix[i], matrix[i].size(),target)){    isOk=true;    return isOk;    }    }return isOk;    }