LeetCode-27.Remove Element
来源:互联网 发布:普罗米修斯白板的软件 编辑:程序博客网 时间:2024/05/17 22:56
Given an array and a value, remove all instances of that value in place and return the new length.
Do not allocate extra space for another array, you must do this in place with constant memory.
The order of elements can be changed. It doesn't matter what you leave beyond the new length.
Example:
Given input array nums = [3,2,2,3]
, val = 3
Your function should return length = 2, with the first two elements of nums being 2.
public int RemoveElement(int[] nums, int val) { int p = 0; for (int i = 0; i < nums.Length; i++) { if (nums[i] != val) nums[p++] = nums[i]; } return p; }
0 0
- [LeetCode]27.Remove Element
- LeetCode --- 27. Remove Element
- LeetCode 27.Remove Element
- [Leetcode] 27. Remove Element
- [Leetcode] 27.Remove Element
- 【leetcode】27. Remove Element
- 【leetcode】27. Remove Element
- Leetcode 27. Remove Element
- LeetCode 27. Remove Element
- 27. Remove Element LeetCode
- 【LeetCode】27. Remove Element
- leetcode 27. Remove Element
- leetcode 27. Remove Element
- [LeetCode]27. Remove Element
- LeetCode 27. Remove Element
- [leetcode] 27. Remove Element
- [leetcode] 27. Remove Element
- leetcode 27. Remove Element
- Camera Roll API + Upload From Camera Roll Module
- NGINX引入线程池 性能提升9倍
- js复制内容到剪贴板代码,js复制代码
- button按钮与文字链接显示效果一样
- iOS UISearchBar改变搜索框的颜色
- LeetCode-27.Remove Element
- c++中字符串的输入
- JSONKit 解析后存在NSULL对象导致的Crash问题处理
- reactnative滑动删除
- C# HttpWebRequest 请求 常出现的问题
- leetcode-19-Remove Nth Node From End of List
- iOS 统计代码行数
- Android安全攻防战,反编译与混淆技术完全解析(下)
- 网络仿真工具TOTEM之——mpls构建LSP