HDOJ(HDU) 2317 Nasty Hacks(比较、)
来源:互联网 发布:数据时代的坏 编辑:程序博客网 时间:2024/04/29 15:32
Problem Description
You are the CEO of Nasty Hacks Inc., a company that creates small pieces of malicious software which teenagers may use
to fool their friends. The company has just finished their first product and it is time to sell it. You want to make as much money as possible and consider advertising in order to increase sales. You get an analyst to predict the expected revenue, both with and without advertising. You now want to make a decision as to whether you should advertise or not, given the expected revenues.
Input
The input consists of n cases, and the first line consists of one positive integer giving n. The next n lines each contain 3 integers, r, e and c. The first, r, is the expected revenue if you do not advertise, the second, e, is the expected revenue if you do advertise, and the third, c, is the cost of advertising. You can assume that the input will follow these restrictions: -106 ≤ r, e ≤ 106 and 0 ≤ c ≤ 106.
Output
Output one line for each test case: “advertise”, “do not advertise” or “does not matter”, presenting whether it is most profitable to advertise or not, or whether it does not make any difference.
Sample Input
3
0 100 70
100 130 30
-100 -70 40
Sample Output
advertise
does not matter
do not advertise
嗯。。水题。。
题意就是输入的:
第一个数a是:做研发能赚多少钱,负数代表亏多少钱。
第二个数b是:做广告能赚多少钱。
第三个数c是:做广告的成本。
也就是比较a和(b+c)谁大谁小,还是相等。
如果a大:输出:do not advertise
如果a小:输出:advertise
如果一样大:输出:does not matter
import java.util.Scanner;public class Main{ public static void main(String[] args) { Scanner sc = new Scanner(System.in); int t =sc.nextInt(); while(t-->0){ int a =sc.nextInt(); int b =sc.nextInt(); int c =sc.nextInt(); if(a==(b-c)){ System.out.println("does not matter"); }else if(a>(b-c)){ System.out.println("do not advertise"); }else{ System.out.println("advertise"); } } }}
- HDOJ(HDU) 2317 Nasty Hacks(比较、)
- HDOJ 2317 Nasty Hacks
- HDU 2317 Nasty Hacks
- hdu-2317-Nasty Hacks
- HDU 2317 Nasty Hacks
- HDU-2317-Nasty Hacks
- hdu 2317 Nasty Hacks
- hdu 2317 Nasty Hacks
- HDOJ 2317 Nasty Hacks(水题)
- Nasty Hacks HDU
- 2317:Nasty Hacks
- Nasty Hacks 2317
- hd 2317 Nasty Hacks
- POJ 3030 && HDU 2317 Nasty Hacks(水~)
- Nasty Hacks
- Nasty Hacks
- 杭电2317题 Nasty Hacks
- POJ 3030 Nasty Hacks
- win10下的 Genymoyion下的配置
- EXPLOITING CVE-2016-2060 ON QUALCOMM DEVICES
- WPF学习之数据绑定
- iOS获取各种文件目录路径的方法
- Understanding LSTM Networks
- HDOJ(HDU) 2317 Nasty Hacks(比较、)
- Android-视图坐标系
- Linux防火墙开放端口
- C++第五次上机实验其他作业
- 写给那些想成为Linux高手的人
- centos安装kubernetes,calico,nfs
- 李航博士:浅谈我对机器学习的理解
- Next Permutation
- C++编译成功,运行失败之static变量