bfs counting sheeps

Counting Sheep

Time Limit : 2000/1000ms (Java/Other)   Memory Limit : 32768/32768K (Java/Other)

Total Submission(s) : 7   Accepted Submission(s) : 4

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Problem Description

A while ago I had trouble sleeping. I used to lie awake, staring at the ceiling, for hours and hours. Then one day my grandmother suggested I tried counting sheep after I'd gone to bed. As always when my grandmother suggests things, I decided to try it out. The only problem was, there were no sheep around to be counted when I went to bed.


Creative as I am, that wasn't going to stop me. I sat down and wrote a computer program that made a grid of characters, where # represents a sheep, while . is grass (or whatever you like, just not sheep). To make the counting a little more interesting, I also decided I wanted to count flocks of sheep instead of single sheep. Two sheep are in the same flock if they share a common side (up, down, right or left). Also, if sheep A is in the same flock as sheep B, and sheep B is in the same flock as sheep C, then sheeps A and C are in the same flock.


Now, I've got a new problem. Though counting these sheep actually helps me fall asleep, I find that it is extremely boring. To solve this, I've decided I need another computer program that does the counting for me. Then I'll be able to just start both these programs before I go to bed, and I'll sleep tight until the morning without any disturbances. I need you to write this program for me.

Input

The first line of input contains a single number T, the number of test cases to follow.

Each test case begins with a line containing two numbers, H and W, the height and width of the sheep grid. Then follows H lines, each containing W characters (either # or .), describing that part of the grid.

Output

For each test case, output a line containing a single number, the amount of sheep flock son that grid according to the rules stated in the problem description.

Notes and Constraints
0 < T <= 100
0 < H,W <= 100

Sample Input

24 4#.#..#.##.##.#.#3 5###.#..#..#.###

Sample Output

63

Source

代码：

#include <iostream>#include<cstdio>#include<string.h>using namespace std;char map[101][101];int vis[101][101];int m,n,ans;void bfs(int i,int j){        if(map[i][j]=='#'&&i>=0&&i<m&&j>=0&&j<n&&vis[i][j]==0)    {        vis[i][j]=1;       bfs(i+1,j);        bfs(i-1,j);       bfs(i,j+1);       bfs(i,j-1);    }}int main(){   int t;   cin>>t;   while(t--)   {       ans=0;       memset(vis,0,sizeof(vis));       cin>>m>>n;       for(int i=0;i<m;i++)        for(int j=0;j<n;j++)        cin>>map[i][j];         for(int i=0;i<m;i++)        for(int j=0;j<n;j++)            if(map[i][j]=='#'&&vis[i][j]==0)        {            ans++;            bfs(i,j);        }       cout<<ans<<endl;   }    return 0;}