hdoj 2052 Picture
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Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)Total Submission(s): 24258 Accepted Submission(s): 12334
Problem Description
Give you the width and height of the rectangle,darw it.
Input
Input contains a number of test cases.For each case ,there are two numbers n and m (0 < n,m < 75)indicate the width and height of the rectangle.Iuput ends of EOF.
Output
For each case,you should draw a rectangle with the width and height giving in the input.
after each case, you should a blank line.
after each case, you should a blank line.
Sample Input
3 2
Sample Output
+---+| || |+---+
Author
xhd
Source
校庆杯Warm Up
代码:
#include <iostream>#include <cstring>#include <cstdio>using namespace std;int a[1010][1010];int main(){ int n,m; while(~scanf("%d%d",&n,&m))//几个循环没有没有套路可言 { memset(a,0,sizeof(a)); a[0][0]=1; a[0][n+1]=1; a[m+1][0]=1; a[m+1][n+1]=1; for(int i=1;i<=n;i++) { a[0][i]=2; a[m+1][i]=2; } for(int j=1;j<=m;j++) { a[j][0]=3; a[j][n+1]=3; } for(int i=0;i<=m+1;i++) { for(int j=0;j<=n+1;j++) { if(a[i][j]==1) printf("+"); else if(a[i][j]==2) printf("-"); else if(a[i][j]==3) printf("|"); else printf(" "); } printf("\n"); } printf("\n"); } return 0;}
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