Leetcode 237. Delete Node in a Linked List

Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.

Supposed the linked list is 1 -> 2 -> 3 -> 4 and you are given the third node with value3, the linked list should become1 -> 2 -> 4 after calling your function.

/** * Definition for singly-linked list. * struct ListNode { *     int val; *     ListNode *next; *     ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public:    void deleteNode(ListNode* node) {        ListNode* nextnode=node->next;        node->val = nextnode->val;        node->next = nextnode->next;        //node->next = NULL;    }};

原本我是想直接复制的：node=node->next；就是用“=”将结构体直接复制，但是出错了，

于是我查询资料发现这样不对，虽然在网上看到有些人用memcpy（）函数直接复制，可是这样也不是完全正确的；

下面是我对memcpy（）函数的理解，仅供参考。

void * memcpy ( void * dest, const void * src, size_t num );

可知memcpy是复制内存地址，而不是复制具体的值，memcpy会按字节复制，所以如果dest和src所指向的有效内存不一致就会出错