3. Longest Substring Without Repeating Characters
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Given a string, find the length of the longest substring without repeating characters.
Examples:
Given "abcabcbb"
, the answer is "abc"
, which the length is 3.
Given "bbbbb"
, the answer is "b"
, with the length of 1.
Given "pwwkew"
, the answer is "wke"
, with the length of 3. Note that the answer must be a substring, "pwke"
is a subsequence and not a substring.
public class Solution { public int lengthOfLongestSubstring(String s) { int[] last = new int[128]; int start = 0; int len = 0; char[] w = new char[s.length()]; w = s.toCharArray(); for(int i = 0; i < 128; i++) last[i] = -1;//last数组用于保存新出现的字符的下标,一开始全部初始化为-1 for(int i = 0; i < s.length(); ++i){ if(last[w[i]-' '] >= start){ //当前这个字符出现过 if(i-start > len) len = i-start; start = last[w[i]-' '] + 1; //从这个字符首次出现的位置+1,重新扫描,相当于把前面抛开前面的字符串不谈 } last[w[i]-' '] = i;//更新当前字符的下标 } if(len > s.length() - start)//针对没有重复字符的字符串 return len; else return s.length() - start; }}
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