python challenge心得

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0.

pow(2,38)
或者2**38

1.

def f(str):    l=[]    for x in str:        if 'a'<=x<='z' or 'A'<=x<='Z':            x=chr((ord(x)+2-ord('a'))%26+ord('a'))        l.append(x)    return ''.join(l)s="g fmnc wms bgblr rpylqjyrc gr zw fylb. rfyrq ufyr amknsrcpq ypc dmp. bmgle gr gl zw fylb gq glcddgagclr ylb rfyr'q ufw rfgq rcvr gq qm jmle. sqgle qrpgle.kyicrpylq() gq pcamkkclbcb. lmu ynnjw ml rfc spj."print f('map')

2.

def f(file):    l=[]    f=open(file,'r')    w=f.read()    for i in w:        if 'a'<=i<='z' or 'A'<=i<='Z':            l.append(i)    return ''.join(l)print f('y.txt')

3.

import urllib2,ref=urllib2.urlopen('http://www.pythonchallenge.com/pc/def/equality.html')ans=''data=f.read()pattern = '[a-z][A-Z]{3}([a-z])[A-Z]{3}[a-z]'print ''.join(re.findall(pattern,data))

得到linkedlist

4.

import urllib2,rer=re.compile(r'(\d+)$')result='12345'while (1):    try:        f=urllib2.urlopen("http://www.pythonchallenge.com/pc/def/linkedlist.php?nothing=%s"%result)        data=f.read()        print data        f.close()        old=result        result=r.search(data).group()    except:        result=old

5.

pickle 序列化与反序列化将数据反序列化（loads()）为list

import picklef=open('5.txt')text=f.read()obj=pickle.loads(text)for list in obj:    print ''.join(t[0]*t[1] for t in list)f.close()

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