Oil Deposits
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又到了水题的时候了
这次分别用c和c++写了两个,很奇怪
用c写的最后结果出错了
有待改正。。。。等哪天找个大神来帮我吧
下来是c++解法
#include <iostream>#include <stdio.h>using namespace std;char map[101][101];int n, m, a[100],t=0;void dfs(int i, int j) { if (map[i][j] != '@' || i < 0 || j < 0 || i >= m || j >= n) { return; } else { map[i][j] = '!'; dfs(i - 1, j - 1); dfs(i - 1, j); dfs(i - 1, j + 1); dfs(i, j - 1); dfs(i, j + 1); dfs(i + 1, j - 1); dfs(i + 1, j); dfs(i + 1, j + 1); }
}
int main()
{
int i, j; while (cin >> m >> n) { if (m == 0 || n == 0) { break; } a[t] = 0; for (i = 0; i < m; i++) for (j = 0; j < n; j++) { cin >> map[i][j]; } for (i = 0; i < m; i++) { for (j = 0; j < n; j++) { if (map[i][j] == '@') { dfs(i, j); a[t]++; } } } t++; } for(i=0;i<t;i++) { printf("%d\n",a[i]); } return 0;
}
下来是c的解法可惜错了
#include<stdio.h>#define N 100int a[N] ;char b[100][100];int i, j, k, n, m, t = 0;void dfs(int i, int j ) { if (b[i][j] != '@' || i < 0 || j > 0 || i >= m || j >= n) { return ; } else { b[i][j] = '!'; dfs(i-1, j-1); dfs(i-1,j); dfs(i-1,j+1); dfs(i, j-1); dfs(i, j + 1); dfs(i + 1, j); dfs(i + 1, j - 1); dfs(i + 1, j + 1); } }int main() { scanf("%d%d", &m, &n); k = getchar(); while (m && n) { a[t]=0; for (i = 0; i < m; i++) { for (j = 0; j < n; j++) { scanf("%c", &b[i][j]); } k = getchar(); } for (i = 0; i < m; i++) { for (j = 0; j < n; j++) { if (b[i][j] == '@') { dfs(i, j); a[t]++; } } } t++; scanf("%d%d",&m,&n); } for (i = 0; i < t; i++) { printf("%d\n", a[i]); } return 0; }
未来会更正~
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