iOS 构造json并提交到服务器

来源：互联网发布：不安全网络怎么解决编辑：程序博客网时间：2024/05/22 14:42

这是服务器要求提交的json数据格式：

data: [
{
"good_id": "2168",
"participants_number": "1",
}

{
"good_id": "2169",
"participants_number": "3",
}
]

1、构造json并提交数据：

- (void) commitOrder:(NSArray *)good_orderAry{

//构造json

NSMutableArray *paramDataAry = [NSMutableArrayarray];

[good_orderAry enumerateObjectsUsingBlock:^(id _Nonnull obj, NSUInteger idx,BOOL * _Nonnull stop) {

NSDictionary *dataDic = (NSDictionary *)obj;

NSMutableDictionary <NSString *,NSString*> *dicParam = [NSMutableDictionary<NSString*,NSString*>dictionaryWithCapacity:2];

[dicParamsetObject:dataDic[@"good_id"]forKey:@"good_id"];

[dicParamsetObject:dataDic[@"participants_number"]forKey:@"participants_number"];

[paramDataAry addObject dicParam];

}];

NSData *jsonData = [NSJSONSerializationdataWithJSONObject:paramDataAryoptions:NSJSONWritingPrettyPrintederror:nil];

NSString *jsonString = [[NSStringalloc] initWithData:jsonDataencoding:NSUTF8StringEncoding];

NSDictionary *param = @{@"data": jsonString};

//提交json数据，AFHTTPSessionManager封装的接口

[PostHttpRequest url:COMMIT_ORDERparameters: param progress:^(NSProgress *uploadProgress) {

} blockCompletion:^(NSDictionary *dataDic) {

self.resultCommitOrderDic = dataDic;

} failure:^{

}];

}

//有疑问可以一块讨论：我的qq：1246489125

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