Java--银行账户存取款线程设计1（交互线程）

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线程之间可能无关，也可能交互。
而线程的同步机制并发执行的交互线程间存在与时间有关的错误。

public class account {    private String name;    private double balance;    public account(String name) {        this.name = name;        this.balance=0;    }    public String getName() {        return name;    }    public double getBalance() {        return balance;    }    //    public void put(double value){        if(value>0){            this.balance=this.balance+value;        }    }    public double  get(double value){        if(value>0){            if(value<=balance){                this.balance=this.balance-value;            }else{                value=this.balance;                this.balance=0;            }        }        return value;    }}

public class save extends Thread{    private account a;    private double value;    public save(account a, double value) {        this.a = a;        this.value = value;    }    public void run() {        double b=a.getBalance();        a.put(value);        System.out.println(a.getName()+"账户，现有"+b+",存入"        +value+"，余额"+a.getBalance());    }}

public class fetch extends Thread{    private account a;    private double value;    public fetch(account a, double value) {        this.a = a;        this.value = value;    }    public void run() {        double b=a.getBalance();        System.out.println(a.getName()+"账户，现有"+b+",取出"        +a.get(value)+"，余额"+a.getBalance());    }}

public class bank {    public static void main(String[] args) {//      account a1=new account("wang");//      save s1=new save(a1,100);//      save s1=new save(new account("wang"),100);//      s1.start();        account a1=new account("wang");        new save(a1,100).start();        new save(a1,200).start();        new fetch(a1,300).start();        new save(new account("xu"),100).start();    }}

运行结果1：
wang账户，现有0.0,存入100.0，余额100.0
wang账户，现有100.0,取出100.0，余额0.0
wang账户，现有0.0,存入200.0，余额200.0
xu账户，现有0.0,存入100.0，余额100.0
运行结果2：
wang账户，现有0.0,存入100.0，余额100.0
wang账户，现有100.0,存入200.0，余额300.0
xu账户，现有0.0,存入100.0，余额100.0
wang账户，现有300.0,取出300.0，余额0.0
由运行结果可以看出，线程很乱

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