java并发编程：顺序输出A、B、C循环10次

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要求：3个线程，分别输出A、B、C。循环10次，给出三种方法，code如下

一、wait、notify

public class PrintABC {static int state = 0;private static Object o = new Object();public static void main(String[] args) {ExecutorService ser = Executors.newCachedThreadPool();ser.submit(new ThreadA());ser.submit(new ThreadB());ser.submit(new ThreadC());ser.shutdown();}public static class ThreadA implements Runnable {@Overridepublic void run() {for(int i=0;i<10;i++){synchronized (o) {while(state%3!=0){try {o.wait();} catch (InterruptedException e) {e.printStackTrace();}}System.out.println("A");state++;o.notifyAll();}}}}public static class ThreadB implements Runnable {@Overridepublic void run() {for(int i=0;i<10;i++){synchronized (o) {while(state%3!=1){try {o.wait();} catch (InterruptedException e) {e.printStackTrace();}}System.out.println("B");state++;o.notifyAll();}}}}public static class ThreadC implements Runnable {@Overridepublic void run() {for(int i=0;i<10;i++){synchronized (o) {while(state%3!=2){try {o.wait();} catch (InterruptedException e) {e.printStackTrace();}}System.out.println("C");state++;o.notifyAll();}}}}}

二、lock、unlock

public class PrintABC2 {static int state = 0;private static Lock lock = new ReentrantLock();public static void main(String[] args) {ExecutorService ser = Executors.newCachedThreadPool();ser.submit(new ThreadA());ser.submit(new ThreadB());ser.submit(new ThreadC());ser.shutdown();}public static class ThreadA implements Runnable {@Overridepublic void run() {for(int i=0;i<10;){lock.lock();if(state%3==0){System.out.println("A");state++;i++;}lock.unlock();}}}public static class ThreadB implements Runnable {@Overridepublic void run() {for(int i=0;i<10;){lock.lock();if(state%3==1){System.out.println("B");state++;i++;}lock.unlock();}}}public static class ThreadC implements Runnable {@Overridepublic void run() {for(int i=0;i<10;){lock.lock();if(state%3==2){System.out.println("C");state++;i++;}lock.unlock();}}}}

三、信号量

public class PrintABC3 {static int state = 0; private static Semaphore A = new Semaphore(1);     private static Semaphore B = new Semaphore(1);     private static Semaphore C = new Semaphore(1);public static void main(String[] args) {ExecutorService ser = Executors.newCachedThreadPool();try {B.acquire();C.acquire();} catch (InterruptedException e) {// TODO Auto-generated catch blocke.printStackTrace();}ser.submit(new ThreadA());ser.submit(new ThreadB());ser.submit(new ThreadC());ser.shutdown();}      static class ThreadA extends Thread {          @Override         public void run() {             try {                 for (int i = 0; i < 10; i++) {                    A.acquire();                     System.out.print("A");                     sleep(2000);                     B.release();                 }             } catch (InterruptedException e) {                 e.printStackTrace();             }         }              }         static class ThreadB extends Thread {      @Override         public void run() {             try {                 for (int i = 0; i < 10; i++) {                    B.acquire();                     System.out.print("B");                     C.release();                 }             } catch (InterruptedException e) {                 e.printStackTrace();             }         }              }          static class ThreadC extends Thread { @Override         public void run() {             try {                 for (int i = 0; i < 10; i++) {                    C.acquire();                     System.out.print("C");                     A.release();                 }             } catch (InterruptedException e) {                 e.printStackTrace();             }         }              }     }

结果如下：

ABCABCABCABCABCABCABCABCABCABC

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