九度 OJ 1004：Median

题目1004：Median

时间限制：1 秒

内存限制：32 兆

特殊判题：否

提交：17340

解决：4807

题目描述：

    Given an increasing sequence S of N integers, the median is the number at the middle position. For example, the median of S1={11, 12, 13, 14} is 12, and the median of S2={9, 10, 15, 16, 17} is 15. The median of two sequences is defined to be the median of the non-decreasing sequence which contains all the elements of both sequences. For example, the median of S1 and S2 is 13.
    Given two increasing sequences of integers, you are asked to find their median.

输入：

    Each input file may contain more than one test case.
    Each case occupies 2 lines, each gives the information of a sequence. For each sequence, the first positive integer N (≤1000000) is the size of that sequence. Then N integers follow, separated by a space.
    It is guaranteed that all the integers are in the range of long int.

输出：

    For each test case you should output the median of the two given sequences in a line.

样例输入：

4 11 12 13 145 9 10 15 16 17

样例输出：

13

来源：

2011年浙江大学计算机及软件工程研究生机试真题

这题最简单的应该就是直接sort了，之前变量类型用的long int ,题中要求的是long int ，但是超时，结果改成int 还过了，不知道怎么搞得，这个变量类型一直不清不白的

#include <iostream>#include <cmath>#include<cstdio>#include<cstring>#include<algorithm>using namespace std;#define N 2000000int P[N];int main(){    int m,n;    while(scanf("%d",&m)!=EOF){        for(int i=0;i<m;i++){            scanf("%d",&P[i]);        }        scanf("%d",&n);        for(int i=m;i<n+m;i++){            scanf("%d",&P[i]);        }        sort(P,P+m+n);        printf("%d\n",P[(m+n+1)/2-1]);    }} /**************************************************************    Problem: 1004    User: th是个小屁孩    Language: C++    Result: Accepted    Time:0 ms    Memory:9332 kb****************************************************************/