350. Intersection of Two Arrays II【E】

Given two arrays, write a function to compute their intersection.

Example:
Given nums1 = [1, 2, 2, 1], nums2 = [2, 2], return [2, 2].

Note:

• Each element in the result should appear as many times as it shows in both arrays.
• The result can be in any order.

Follow up:

• What if the given array is already sorted? How would you optimize your algorithm?
• What if nums1's size is small compared to num2's size? Which algorithm is better?
• What if elements of nums2 are stored on disk, and the memory is limited such that you cannot load all elements into the memory at once?

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class Solution(object):    def intersect(self, nums1, nums2):                nums1.sort()        nums2.sort()                res = []        i = 0        j = 0        while i < (len(nums1)) and j < (len(nums2)):            #print i,j            if nums1[i] == nums2[j]:                                res += nums1[i],                i += 1                j += 1                            elif nums1[i] < nums2[j]:                i += 1                            else:                j += 1        return res