hdoj2055An easy problem

Problem Description

we define f(A) = 1, f(a) = -1, f(B) = 2, f(b) = -2, ... f(Z) = 26, f(z) = -26;
Give you a letter x and a number y , you should output the result of y+f(x).

 

Input

On the first line, contains a number T.then T lines follow, each line is a case.each case contains a letter and a number.

 

Output

for each case, you should the result of y+f(x) on a line.

 

Sample Input

6R 1P 2G 3r 1p 2g 3

 

Sample Output

191810-17-14-4

 刚开始循环进行到一半就停止了，后来在每个scanf后加个getchar();然后就AC了，不知道为什么，求大神指点

AC代码如下：

#include<stdio.h>int main(){int n;scanf("%d",&n);getchar();while(n--){int y;char x;scanf("%c",&x);getchar();scanf("%d",&y);getchar();if(x>=65&&x<=90)printf("%d\n",x-'A'+1+y);else if(x>=97&&x<=122)printf("%d\n",(x-'a'+1)*(-1)+y);}}