Substring with Concatenation of All Words
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题目描述:
You are given a string, s, and a list of words, words, that are all of the same length. Find all starting indices of substring(s) ins that is a concatenation of each word inwords exactly once and without any intervening characters.
For example, given:
s: "barfoothefoobarman"
words: ["foo", "bar"]
You should return the indices: [0,9]
.
(order does not matter).
最笨的办法就是枚举出来所有的子集,然后再从S中得到相应的index、不出意外超时了。
后来用hashtable,创建map<string,integer>,int记录单词的个数,这样也超时了。此时的复杂度是O(m*n):
后来参考了别人的做法,实在是巧妙。
0 0
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