【CodeForces】#621A - Wet Shark and Odd and Even(水)
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Today, Wet Shark is given n integers. Using any of these integers no more than once, Wet Shark wants to get maximum possible even (divisible by 2) sum. Please, calculate this value for Wet Shark.
Note, that if Wet Shark uses no integers from the n integers, the sum is an even integer 0.
The first line of the input contains one integer, n (1 ≤ n ≤ 100 000). The next line contains n space separated integers given to Wet Shark. Each of these integers is in range from 1 to 109, inclusive.
Print the maximum possible even sum that can be obtained if we use some of the given integers.
31 2 3
6
5999999999 999999999 999999999 999999999 999999999
3999999996
In the first sample, we can simply take all three integers for a total sum of 6.
In the second sample Wet Shark should take any four out of five integers 999 999 999.
题意:让给出的数的和为偶数,并且使之最大。
思路:在输入阶段统计所有的和,并更新最小的奇数,如果最后和为偶数的话,直接输出;如果和为奇数,减去最小的奇数即可。
代码如下:
#include <cstdio>#include <algorithm>using namespace std;int main(){int n;__int64 sum = 0;int mi = 0x7fffffff;scanf ("%d",&n);while (n--){int t;scanf ("%d",&t);sum += t;if (t & 1)mi = min (t , mi);}if (sum & 1)printf ("%I64d\n",sum - mi);elseprintf ("%I64d\n",sum);return 0;}
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