shell脚本中数组的使用

1.数组的基本用法

引用数组的形式：${arry[x]}

#!/bin/bash city=(nanjing beijing jinan zibo linyi)echo "city[0]=${city[0]}"echo "city[1]=${city[1]}"echo "city[2]=${city[2]}"echo "city[3]=${city[3]}"echo "city[4]=${city[4]}"echo "city[5]=${city[5]}" ~                                                                                                                                                                       ~                                                                                                                                                                       ~                                                                                                                                                                       ~                                                                                                                                                                       运行结果：~    [root@nn shell]# chmod +x arry1.sh [root@nn shell]# ./arry1.sh city[0]=nanjingcity[1]=beijingcity[2]=jinancity[3]=zibocity[4]=linyicity[5]=#!/bin/bash city=(nanjing [3]=beijing jinan zibo linyi)   //()可以给任意一个元素随机赋值echo "city[0]=${city[0]}"echo "city[1]=${city[1]}"echo "city[2]=${city[2]}"echo "city[3]=${city[3]}"echo "city[4]=${city[4]}"echo "city[5]=${city[5]}"~运行结果：                                                                                                                                                                       ~[root@nn shell]# ./arry1.sh city[0]=nanjingcity[1]=city[2]=city[3]=beijingcity[4]=jinancity[5]=zibo              

2.用@ 和 * 都可以表示数组元素的值

#!/bin/bash city=(nanjing [3]=beijing jinan zibo linyi)for i in ${city[@]}doecho $idone

运行结果：

[root@nn shell]# ./arry1.sh
nanjing
beijing
jinan
zibo
linyi

当然用* 和用@一样。。。当然当数组元素中存在空格基于用引号引起来

${city[@]}   用引号引起来是，“${city[@]}” 和“${city[*]}”有一点不一样的地方就是<pre name="code" class="html">“${city[@]}”分行打印，“${city[*]}”在同一行打印