LeetCode:Binary Tree Inorder Traversal

Binary Tree Inorder Traversal

Total Accepted: 126544 Total Submissions: 316559 Difficulty: Medium

Given a binary tree, return the inorder traversal of its nodes' values.

For example:
Given binary tree {1,#,2,3},

   1    \     2    /   3

return [1,3,2].

Note: Recursive solution is trivial, could you do it iteratively?

confused what "{1,#,2,3}" means? > read more on how binary tree is serialized on OJ.

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c++ code:

/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    vector<int> inorderTraversal(TreeNode* root) {        vector<int> ivec;        TreeNode *p=root;        stack<TreeNode *> s;        while(p || !s.empty()){            while(p){                s.push(p);                p=p->left;            }            if(!s.empty()){                p=s.top();                ivec.push_back(p->val);                s.pop();                p=p->right;            }        }        return ivec;    }};