c/akari（2011iooo)的格式化后的代码

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1. #include<stdio.h>  
2.   
3. int main(int n,char **m)  
4. {  
5.     FILE*p,*q;  
6.     int        A,k,a,r,i;  
7.     char*d="P%"   "d\n%d\40%d"  
8.            "\n%d\n\00wb+",b[1024],y[]="yuriyurarararayuruyuri*daijiken**akkari~n**"  
9.                                       "/y*u*k/riin<ty(uyr)g,aur,arr[a1r2a82*y2*/u*r{uyu}riOcyurhiyua**rrar+*arayra*="  
10.                                       "yuruyurwiyuriyurara'rariayuruyuriyuriyu>rarararayuruy9uriyu3riyurar_aBrMaPrOaWy^?"  
11.                                       "*]/f]`;hvroai<dp/f*i*s/<ii(f)a{tpguat<cahfaurh(+uf)a;f}vivn+tf/g*`*w/jmaa+i`ni("/** 
12.      */"i+k[>+b+i>++b++>l[rb";  
13.     int u;  
14.     for(i=0; i<101; i++)y[i*2]^="~hktrvg~dmG*eoa+%squ#l2"  
15.                                     ":(wn\"1l))v?wM353{/Y;lgcGp`vedllwudvOK`cct~[|ju {stkjalor(stwvne\"gt\"yogYURUYURI"[  
16.                                         i]^y[i*2+1]^4;  
17.     p=(n>1&&(m[1][0]-'-'||m[1][1]  !='\0'))?fopen(m[1],y+298):stdin;  
18.     q=(n<3||!(m[2][0]-'-'||m[2][1]))?stdout :fopen(m[2],d+14);  
19.     if(!p||!q)  
20.         return+printf("Can "  "not\x20open\40%s\40"    ""       "for\40%sing\n",m[!p?1:2],!p?"read":"writ");  
21.     for  (   a=k=u= 0; y[u];  u=2    +u) {  
22.         y[k++   ]=y[u];  
23.     }  
24.     if((a=fread(b,1,1024,p) )>2&& b[0]=='P' &&4==sscanf(b,d,&k,& A,&i,  &r)&& !(k-6&&k -5)&&r==255) {  
25.         u=A;  
26.         if(n>3) {  
27.             u++;  
28.             i++;  
29.         }  
30.         fprintf(q, d,k, u>>1,i>>1,r);  
31.         u  = k-5?8:4;  
32.         k=3;  
33.     } else  
34.         {  
35.         (u)=+(n+14>17)?8/4:8*5/4;  
36.     }  
37.     for(r=i=0  ;  ;) {  
38.         u*=6;  
39.         u+=                (n>3?1:0);  
40.         if (y[u]&01)fputc(1*(r),q);  
41.         if (y[u]&16)k=A;  
42.         if (y[u]&2)k--;  
43.         if(i==a) {  
44.             i=a=(u)*11&255;  
45.             if(1&&0>=(a=fread(b,1,1024,p))&&  
46.                ")]i>(w)-;} {                                         /i-f-(-m--M1-0.)<{"[ 8]==59)break;  
47.             i=0;  
48.         }  
49.         r=b[i++];  
50.         u+=(+8&*(y+u))?(10-r?4:2):(y[u]&4)?(k?2:4):2;  
51.         u=y[u]-(int)'`';  
52.     }  
53.     fclose(p);  
54.     k= +fclose( q);  
55.     return  k- -1+ (-0x01);  
56. }