leetcode #50 in cpp

来源:互联网 发布:联想网络销售授权店 编辑:程序博客网 时间:2024/05/22 06:37

Implement pow(xn).

Solution:

Brute force method is to have x^n = x*x*.....*x. 

We use divide and conquer method pow(x,n) = pow(x,n/2)^2 if n is even or pow(x,n) = x*pow(x,n-1) if n is odd. 

Code:

class Solution {public:    double myPow(double x, int n) {        if(x==1 || x==0) return x;        if(x==-1) return n%2?-1:1;                if(n==1) return x;        if(n==0) return 1;                if(n==INT_MIN || n == INT_MAX || x == INT_MIN  || x==INT_MAX ) return 0.0;                if(n < 0){            return 1/pow(x,-n);        }else{            return pow(x,n);        }    }    double pow(double x, int n){        if(n==1){            return x;        }        //if(n==0) return 1;        if(n%2){//odd number            return x*myPow(x,n-1);        }else{//even number            double temp = myPow(x,n/2);            return temp*temp;        }    }};


0 0
原创粉丝点击