Middle-题目77:92. Reverse Linked List II
来源:互联网 发布:中铁九局怎么样 知乎 编辑:程序博客网 时间:2024/06/06 02:29
题目原文:
Reverse a linked list from position m to n. Do it in-place and in one-pass.
For example:
Given 1->2->3->4->5->NULL, m = 2 and n = 4,
return 1->4->3->2->5->NULL.
题目大意:
给出一个单链表和两个数m,n,翻转链表的m~n位。
题目分析:
还是用two pointers的思想,记住m的前驱,令其后继指向n,而n的后继指向m的next,以此类推。(在纸上画画,并多考虑一些特殊情况,如m是开头,n是结尾等)
源码:(language:c)
struct ListNode* reverseBetween(struct ListNode* head, int m, int n) { if (m == n || !head || !head->next) return head; int i = 1; struct ListNode* mPtr = head, *nPtr = head; for (struct ListNode* node = head; node; node = node->next, i++) { if (i == m) mPtr = node; if (i == n) nPtr = node; } if (mPtr == head) { while (mPtr != nPtr) { struct ListNode* temp = mPtr; mPtr = mPtr->next; temp->next = nPtr->next; nPtr->next = temp; } return nPtr; } else { struct ListNode* mPtrPrev = head; while (mPtrPrev->next != mPtr) mPtrPrev = mPtrPrev->next; mPtrPrev->next = nPtr; while (mPtr != nPtr) { struct ListNode* temp = mPtr; mPtr = mPtr->next; temp->next = nPtr->next; nPtr->next = temp; } return head; } }
成绩:
0ms,100%
Cmershen的碎碎念:
这道题在纯链表节点处理的题里面算是较难的了,须结合源码并在纸上演示一下才能理解指针间的关系。
0 0
- Middle-题目77:92. Reverse Linked List II
- Middle-题目50:142. Linked List Cycle II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- 92. Reverse Linked List II
- Middle-题目76:47. Permutations II
- 五月份英语总结
- uva 10180 Rope Crisis in Ropeland!
- 『QT』创客空间元件管理系统
- Android实现动画过程中遇到View.mViewFlags on null object refrence
- Middle-题目77:92. Reverse Linked List II
- SpringMVC框架上传表单时怎么将表单数据与实体对象绑定,然后在控制器中调用
- 图解 debounce 与 throttle 的区别
- node.js调用C++说明文档
- 01串 DP
- poj 3292 Semi-prime H-numbers (打表 同余模运算)
- Linux进程控制块 task_struct
- Android UI Libs之CircleImageView
- MongoDB初学之环境的搭建