过滤器配置

来源：互联网发布：数学不好可以学编程吗编辑：程序博客网时间：2024/05/27 21:48

在web.xml里配置，截取url，然后进入LoginFilter

<filter>    <filter-name>login</filter-name>    <filter-class>model.LoginFilter</filter-class></filter><filter-mapping>    <filter-name>login</filter-name>    <url-pattern>/*</url-pattern></filter-mapping>

LoginFilter

package model;import java.io.IOException; ::::::import javax.servlet.http.HttpSession; public class LoginFilter implements Filter {    @Override     public void doFilter(ServletRequest request, ServletResponse response,             FilterChain chain) throws IOException, ServletException {        // 获得在下面代码中要用的request,response,session对象        HttpServletRequest servletRequest = (HttpServletRequest) request;         HttpServletResponse servletResponse = (HttpServletResponse) response;         HttpSession session = servletRequest.getSession();        // 获得用户请求的URI        String path = servletRequest.getServletPath();         // 无需过滤的：css,js,登录jsp，登录Servlet，wx开头的地址        if(path.indexOf(".css") > 0|| path.indexOf(".js") > 0||path.equals("/index.jsp")||path.equals("/UserLogin")||path.indexOf("wx")>0) {            chain.doFilter(servletRequest, servletResponse);            return;         }        // 从session里取教师信息        Teacher user = (Teacher) servletRequest.getSession().getAttribute("loginUser");             // 判断如果没有取到员工信息,就跳转到登陆页面        if (user == null || "".equals(user)) {             // 跳转到登陆页面            servletResponse.sendRedirect("/english/index.jsp");        } else {            // 已经登陆,继续此次请求            chain.doFilter(request, response);        }    } }

0 0