HDU-2005

题目：http://acm.hdu.edu.cn/showproblem.php?pid=2005

仅供参考：

#include<stdio.h>int main(){int year, month, day,sum;while (scanf("%d/%d/%d", &year, &month, &day) != EOF){sum= 0;//每次循环须将sum初始化为0int m1,m2;m1 = month  / 2;//奇数月数量（不含当前月）sum+= m1 * 31;m2 = month - m1-1;//偶数月数量（不含当前月）if (month > 2){if ((year % 4 == 0 && year % 100 != 0) || year % 400 == 0)//闰年sum += (m2 - 1) * 30 + 29;elsesum += (m2 - 1) * 30 + 28;}sum += day;//加上当前月份天数printf("%d\n", sum);}return 0;}/*方法二：使用switch case语句,switch(month-1),且去掉break语句方法三：先将每个月的天数存储在数组a中，执行a[month]=day（当前月份的天数）,使用循环计算sum的值*/