hdoj-4931-Happy Three Friends

Description
Dong-hao , Grandpa Shawn , Beautful-leg Mzry are good friends. One day , they want to play a game.

There are 6 numbers on the table.

Firstly , Dong-hao can change the order of 6 numbers.

Secondly , Grandpa Shawn take the first one and the last one , sum them up as his scores.

Thirdly , Beautiful-leg Mzry take any of 3 numbers from the last 4 numbers , and sum them up as his scores.

Finally , if Grandpa Shawn’s score is larger than Beautiful-leg Mzry’s , Granpa Shawn wins!

If Grandpa Shawn’s score is smaller than Beautiful-leg Mzry’s , Granpa Shawn loses.

If the scores are equal , there is a tie.

Nowadays , it’s really sad that Grandpa Shawn loses his love. So Dong-hao wants him to win(not even tie). You have to tell Dong-hao whether he can achieve his goal.

Input
There is a number T shows there are T test cases below. ( T <= 50)

For each test case , there are 6 numbers Ai ( 1 <= Ai <= 100 ).

Output
If Dong-hao can achieve his goal , output “Grandpa Shawn is the Winner!”
If he can not , output “What a sad story!”

Sample Input

3
1 2 3 3 2 2
2 2 2 2 2 2
1 2 2 2 3 4

Sample Output

What a sad story!
What a sad story!
Grandpa Shawn is the Winner!

Hint

For the first test case , {3 , 1 , 2 , 2 , 2 , 3} Grandpa Shawn can take 6 at most . But Beautiful-leg Mzry can take 6 too. So there is a tie. For the second test cases , Grandpa Shawn loses. For the last one , Dong-hao can arrange the numbers as {3 , 2 , 2 , 2 , 1 , 4} , Grandpa Shawn can take 7 , but Beautiful-leg Mzry can take 6 at most. So Grandpa Shawn Wins!

算是一个小贪心吧，题意很好懂，水题一个

#include<cstdio>#include<cstring>#include<iostream>#include<algorithm>using namespace std;int main(){    int t;    scanf("%d",&t);    int a[10];    while(t--)    {        int sum=0;        for(int i=0;i<6;i++)        {            scanf("%d",&a[i]);            sum+=a[i];        }        sort(a,a+6);        int cnt=a[4]+a[5];        sum-=(cnt+a[0]);        if(cnt>sum)            printf("Grandpa Shawn is the Winner!\n");        else  printf("What a sad story!\n");    }    return 0;}