把数组排成最小的数

关键在比较两个数字之前谁先放在前面。

 public String PrintMinNumber(int [] numbers){        for(int i = 0;i < numbers.length - 1; i ++) {            for(int j = 0;j < numbers.length - i - 1;j ++) {                int first = numbers[j];                int second = numbers[j + 1];                // 比较两个数                // 获取位数                char[] cArr1 = String.valueOf(first).toCharArray();                char[] cArr2 = String.valueOf(second).toCharArray();                for(int k = 0;k < cArr1.length || k < cArr2.length;k ++) {                    int temp1 = 0,temp2 = 0;                    if(k < cArr1.length)                        temp1 = Integer.valueOf(cArr1[k]);                    else                        temp1 = Integer.valueOf(cArr1[cArr1.length - 1]);                    if(k < cArr2.length)                        temp2 = Integer.valueOf(cArr2[k]);                    else                        temp2 = Integer.valueOf(cArr2[cArr2.length - 1]);                    if(temp2 <= temp1) {                        int t = numbers[j];                        numbers[j] = numbers[j + 1];                        numbers[j + 1] = t;                        break;                    }                }            }        }        StringBuffer sb = new StringBuffer();        for(int number : numbers) {            sb.append(number);        }        return sb.toString();    }