编程之美

1.2 中国象棋问题

public class Solution {    public static void main(String[] args) {             char data = 0x11;//A、B都从1开始             while ((data&0x0F) != 0x0A)//B从1到9             {                  while ((data&0xF0) != 0xA0)//A从1到9                  {                       if ((data&0x0F)%3 != ((data&0xF0)>>4)%3)//A、B二者余数不同，即列不同                           System.out.println("A:" + ((data&0xF0)>>4) + "  B:" +(data&0x0F));                       data += 0x10;//A加1                  }                  data = (char) (data & 0x0F);                  data += 0x11;//A设为1，B加1             }             return ;    }}