LeetCode 352. Data Stream as Disjoint Intervals(数据流区间)
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原题网址:https://leetcode.com/problems/data-stream-as-disjoint-intervals/
Given a data stream input of non-negative integers a1, a2, ..., an, ..., summarize the numbers seen so far as a list of disjoint intervals.
For example, suppose the integers from the data stream are 1, 3, 7, 2, 6, ..., then the summary will be:
[1, 1][1, 1], [3, 3][1, 1], [3, 3], [7, 7][1, 3], [7, 7][1, 3], [6, 7]
Follow up:
What if there are lots of merges and the number of disjoint intervals are small compared to the data stream's size?
方法一:使用集合保存到目前为止的数据集,插入时间O(1),读取时间O(N)
/** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * Interval(int s, int e) { start = s; end = e; } * } */public class SummaryRanges { private Set<Integer> set = new HashSet<>(); /** Initialize your data structure here. */ public SummaryRanges() { } public void addNum(int val) { set.add(val); } public List<Interval> getIntervals() { Set<Integer> s = new HashSet<>(set); List<Interval> list = new ArrayList<>(); while (!s.isEmpty()) { int min = s.iterator().next(); int max = min; s.remove(min); for(int i=max+1;;i++) { if (s.remove(i)) max = i; else break; } for(int i=min-1;; i--) { if (s.remove(i)) min = i; else break; } list.add(new Interval(min, max)); } Collections.sort(list, new Comparator<Interval>() { @Override public int compare(Interval i1, Interval i2) { return i1.start - i2.start; } }); return list; }}/** * Your SummaryRanges object will be instantiated and called as such: * SummaryRanges obj = new SummaryRanges(); * obj.addNum(val); * List<Interval> param_2 = obj.getIntervals(); */
方法二:使用二分法查找区间,插入时间O(logN),读取时间O(1)。
/** * Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * Interval(int s, int e) { start = s; end = e; } * } */public class SummaryRanges { private List<Interval> list = new ArrayList<>(); /** Initialize your data structure here. */ public SummaryRanges() { } public void addNum(int val) { if (list.isEmpty()) { list.add(new Interval(val, val)); return; } int i=0, j=list.size()-1; while (i<=j) { int m = (i+j)/2; Interval interval = list.get(m); if (interval.start <= val && val <= interval.end) return; if (val > interval.start) i=m+1; else j=m-1; } Interval target = i == list.size() ? null : list.get(i); Interval left = i == 0 ? null : list.get(i-1); if (i == 0) { if (val+1 == target.start) { target.start = val; return; } list.add(0, new Interval(val, val)); return; } else if (i==list.size()) { if (left.start <= val && val <= left.end) return; if (left.end+1 == val) { left.end = val; return; } list.add(new Interval(val, val)); return; } else { if (target.start <= val && val <= target.end) return; if (left.start <= val && val <= left.end) return; if (left.end+1 < val && val+1 < target.start) { list.add(i, new Interval(val, val)); return; } if (left.end+1 == val) { left.end = val; } if (val+1 == target.start) { target.start = val; } if (left.end == target.start) { left.end = target.end; list.remove(i); } } } public List<Interval> getIntervals() { return list; }}/** * Your SummaryRanges object will be instantiated and called as such: * SummaryRanges obj = new SummaryRanges(); * obj.addNum(val); * List<Interval> param_2 = obj.getIntervals(); */
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