二进制 120
来源:互联网 发布:初中生学编程考试 编辑:程序博客网 时间:2024/04/29 17:12
Private Sub Command1_Click()
Me.Font.Size = 60
Print erjinzhi(120)
End Sub
Private Function erjinzhi(m As Byte) As String
Dim n As Byte
n = m
Const er As Byte = 2
Dim returnS As String
Dim shang As Byte
Dim yushu(1 To 8) As Byte
Dim i As Byte
i = UBound(yushu)
shang = n \ er '11
yushu(i) = n Mod er '1
returnS = yushu(i)
While shang <> 0
i = i - 1
n = shang '11 5 2 1
shang = n \ er '5 2 1 0
yushu(i) = n Mod er '1 1 0 1
returnS = yushu(i) & returnS
Wend
erjinzhi = returnS
End Function
Me.Font.Size = 60
Print erjinzhi(120)
End Sub
Private Function erjinzhi(m As Byte) As String
Dim n As Byte
n = m
Const er As Byte = 2
Dim returnS As String
Dim shang As Byte
Dim yushu(1 To 8) As Byte
Dim i As Byte
i = UBound(yushu)
shang = n \ er '11
yushu(i) = n Mod er '1
returnS = yushu(i)
While shang <> 0
i = i - 1
n = shang '11 5 2 1
shang = n \ er '5 2 1 0
yushu(i) = n Mod er '1 1 0 1
returnS = yushu(i) & returnS
Wend
erjinzhi = returnS
End Function
0 0
- 二进制 120
- 二进制 120
- 二进制 120
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- 二进制
- Winows 下软链接批处理
- 安卓查看模拟器数据库方法
- 16进制
- jdk和jre的区别!
- [leetcode]40. Combination Sum II ,python实现【medium难度】
- 二进制 120
- iTween
- 华为C语言编程规范—可读性
- 手机号码
- aidl.exe'' finished with non-zero exit value 1和3问题解决
- EJB总结
- 230二进制
- Charles破解