leetcode #113 in cpp

来源:互联网 发布:p2p运营模式数据图表 编辑:程序博客网 时间:2024/06/06 12:33

Given a binary tree and a sum, find all root-to-leaf paths where each path's sum equals the given sum.

For example:
Given the below binary tree and sum = 22,
              5             / \            4   8           /   / \          11  13  4         /  \    / \        7    2  5   1

return

[   [5,4,11,2],   [5,8,4,5]]


Code:

/** * Definition for a binary tree node. * struct TreeNode { *     int val; *     TreeNode *left; *     TreeNode *right; *     TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public:    vector<vector<int>> pathSum(TreeNode* root, int sum) {        vector<vector<int>> res;        vector<int> member;        findSum(root, sum,member, res);        return res;     }    void findSum(TreeNode *root, int sum, vector<int> member, vector<vector<int>> &res){        if(!root) return;         member.push_back(root->val);        if(root->val == sum){            if(!root->left && !root->right){                res.push_back(member);                return;            }        }        findSum(root->left, sum - root->val, member, res);        findSum(root->right, sum - root->val, member, res);            }    };

0 0
原创粉丝点击