hdu1312 深搜 java
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Problem Description
There is a rectangular room, covered with square tiles. Each tile is colored either red or black. A man is standing on a black tile. From a tile, he can move to one of four adjacent tiles. But he can’t move on red tiles, he can move only on black tiles.
Write a program to count the number of black tiles which he can reach by repeating the moves described above.
Input
The input consists of multiple data sets. A data set starts with a line containing two positive integers W and H; W and H are the numbers of tiles in the x- and y- directions, respectively. W and H are not more than 20.
There are H more lines in the data set, each of which includes W characters. Each character represents the color of a tile as follows.
‘.’ - a black tile
‘#’ - a red tile
‘@’ - a man on a black tile(appears exactly once in a data set)
Output
For each data set, your program should output a line which contains the number of tiles he can reach from the initial tile (including itself).
Sample Input
6 9
….#.
…..#
……
……
……
……
……
@…
.#..#.
11 9
.#………
.#.#######.
.#.#…..#.
.#.#.###.#.
.#.#..@#.#.
.#.#####.#.
.#…….#.
.#########.
………..
11 6
..#..#..#..
..#..#..#..
..#..#..###
..#..#..#@.
..#..#..#..
..#..#..#..
7 7
..#.#..
..#.#..
.
…@…
.
..#.#..
..#.#..
0 0
Sample Output
45
59
6
13
import java.util.Scanner;public class P1312 { private static int dir[][]={{-1,0},{1,0},{0,-1},{0,1}};//上下左右 static long max=-1; static long num=0; static int h,w; public static void main(String[] args) { Scanner sc=new Scanner(System.in); while(sc.hasNext()){ w=sc.nextInt(); h=sc.nextInt(); if(w==0&&h==0){ return; } char arr[][]=new char[h][w]; int x = 0,y=0; int vistied[][]=new int[h][w]; for(int i=0;i<arr.length;i++){ String str=sc.next(); for(int j=0;j<arr[i].length;j++){ arr[i][j]=str.charAt(j); vistied[i][j]=0; if(arr[i][j]=='@'){ x=i; y=j; } } } num=1; dfs(arr, x, y,vistied); System.out.println(num); } } private static void dfs(char[][] arr,int a ,int b,int[][] vistied) { for(int i=0;i<dir.length;i++){ int x=dir[i][0]+a; int y=dir[i][1]+b; if(inmap(x,y)&&arr[x][y]=='.'&&vistied[x][y]==0){ num++; vistied[x][y]=1; dfs(arr, x, y, vistied); } } } private static boolean inmap(int a, int b) { if(a<0 || b<0 || a>=h || b>=w){ return false; } return true; }}
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