codeforces202A. Mafia【二分】

A. Mafia

time limit per test

2 seconds

memory limit per test

256 megabytes

input

standard input

output

standard output

One day n friends gathered together to play "Mafia". During each round of the game some player must be the supervisor and othern - 1 people take part in the game. For each person we know in how many rounds he wants to be a player, not the supervisor: the i-th person wants to play ai rounds. What is the minimum number of rounds of the "Mafia" game they need to play to let each person play at least as many rounds as they want?

Input

The first line contains integer n (3 ≤ n ≤ 105). The second line contains n space-separated integers a1, a2, ..., an (1 ≤ ai ≤ 109) — thei-th number in the list is the number of rounds the i-th person wants to play.

Output

In a single line print a single integer — the minimum number of game rounds the friends need to let the i-th person play at least airounds.

Please, do not use the %lld specifier to read or write 64-bit integers in С++. It is preferred to use the cin, cout streams or the%I64d specifier.

Examples

input

33 2 2

output

4

input

42 2 2 2

output

3

Note

You don't need to know the rules of "Mafia" to solve this problem. If you're curious, it's a game Russia got from the Soviet times:http://en.wikipedia.org/wiki/Mafia_(party_game).

#include<iostream>#include<cstdlib>#include<cstring>#include<algorithm>#include<cmath>#include<cstdio>#include<queue>#include<list>#include<stack>#include<queue>using namespace std;const int maxn=100010;long long num[maxn],n;bool judge(long long mid){    long long ans=0;    for(int i=1;i<=n;++i){        if(num[i]>mid)return false;        ans=ans+mid-num[i];    }    return ans>=mid;}int main(){    long long ans=0,left=0,right=0;    scanf("%lld",&n);    for(int i=1;i<=n;++i){        scanf("%lld",&num[i]);        right+=num[i];    }    while(left<=right){        long long mid=(left+right)>>1;        if(judge(mid)){            ans=mid;            right=mid-1;        }        else {            left=mid+1;        }    }    printf("%lld\n",ans);    return 0;}