OC中把字符串倒叙,且每个单词正序, 并计算单词数,两个单词间空格多少不影响结果

来源：互联网发布：2017中国域名总数编辑：程序博客网时间：2024/05/06 01:27

1 OC中把字符串倒叙,且每个单词正序, 并计算单词数,两个单词间空格多少不影响结果@”hello world how are you”,

代码如下
.m

@interface ViewController ()@property (nonatomic , strong )NSString *demo ;//单个单词@property (nonatomic , strong )NSString *resutStr;@end@implementation ViewController//懒加载-(NSString *)resutStr{     if (_resutStr == nil) {        _resutStr = [NSString string];    }    return _resutStr;}-(NSString *)demo{      if (_demo == nil) {        _demo = [NSString string];    }    return _demo;}- (void)viewDidLoad {    [super viewDidLoad];    int  n  = 1 ; //总单词数    NSString *strs = @"hello world  how are you";    NSLog(@"%@",strs);    strs  =  [strs stringByAppendingString:@" "];//长度加1    for (NSInteger i = strs.length - 1 ; i  >= 0 ; i--) {        NSRange range = NSMakeRange(i, 1);        NSString *str  =   [strs substringWithRange:range];         //将几个字母组成的单词倒叙(两次倒叙为正)        if ([str  isEqual: @" "]) {            for (NSInteger m = self.demo.length - 1 ; m >= 0; m--) {                NSRange rangeDemo = NSMakeRange(m, 1);                NSString *strDemo  =   [self.demo substringWithRange:rangeDemo];                //  NSLog(@"%@", strDemo);                //记录输出                self.resutStr =   [self.resutStr stringByAppendingString:strDemo];            }            //只有同时满足下列两个条件才是一个单词            if ( (![self.demo isEqual:@" "]) && (![self.demo isEqual:@""]) ) {                n = n +1 ;            }              self.demo = nil;            }    //将几个字母组成单词,        self.demo =   [self.demo stringByAppendingString:str];    }    //第一个单词不会打印, 另外打印    for (NSInteger m = self.demo.length - 1 ; m >= 0; m--) {        NSRange rangeDemo = NSMakeRange(m, 1);        NSString *strDemo  =   [self.demo substringWithRange:rangeDemo];        if (![strDemo isEqual:@" "]) {            // NSLog(@"%@", strDemo);            self.resutStr =    [self.resutStr stringByAppendingString:strDemo];        }    }    NSLog(@"%@\n 总单词数%d",self.resutStr,n);}

@end

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