237. Delete Node in a Linked List
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Write a function to delete a node (except the tail) in a singly linked list, given only access to that node.
Supposed the linked list is 1 -> 2 -> 3 -> 4
and you are given the third node with value3
, the linked list should become 1 -> 2 -> 4
after calling your function.
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分析:
不要拘泥于遍历然后删除掉某个点。
正确的做法 应该就是拿到这个点后,让这个点的值为下一个点的值,next指向下一个点的next.
删除某节点的两种方法。
一种是跨过这个节点,指向下一个节点。
另一种是赋值这个节点的next节点,然后跨过next节点。对于尾节点,需要另行处理。
本题即属于第二种。
/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */class Solution {public: void deleteNode(ListNode* node) { node->val=node->next->val; node->next=node->next->next; }};
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