Android 编码问题

来源：互联网发布：怎么才能加入淘宝编辑：程序博客网时间：2024/06/03 21:51

php文件存在h盘服务器中，由于记事本默认编码ascII 导致android端使用，UrlHttpConnection类的 GET方法后，获取反馈（echo‘测试文本：登陆成功+123abc’）文本数据时“

@Overridepublic void run() {
{    Looper.prepare();    super.run();    try {        URL url = new URL("http://192.168.1.109/mytest/index.php?name=" + user + "&psw=" + passwd);        HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();        InputStreamReader isr = new InputStreamReader(urlConnection.getInputStream());        BufferedReader br = new BufferedReader(isr);        String readbr;        while ((readbr = br.readLine()) != null)            line += readbr + "\n";//下面的操作都多此一举     //  byte[] byteline = org.apache.commons.codec.binary.Base64.decodeBase64(line.getBytes());    ////    Base64.decode(line,1)    ////    line = new String(byteline,"utf8");        //二进制转到字符称为编码，由字符到二进制称为解码        //str.getBytes("charset");//指定charset，即用底层存储的Unicode码来解析 charset这种编码格式的字节数组方式        //str.getBytes();  如果括号中不写charset，则采用的是Sytem.getProperty("file.encoding"),即当前文件的编码方式，      //Base64.decode(line.getBytes("utf8"));        urlConnection.disconnect();//关闭http连接    } catch (UnknownHostException e) {        e.printStackTrace();        line += e.toString();    } catch (IOException e) {        e.printStackTrace();        line += e.toString();    } finally {        Log.i("Mactivity_Thread", "line = " + line);        Message msg = new Message();        //  msg.set        msg.obj = new String(line);        mHandler.sendMessage(msg);        Looper.loop();    }}

Android activity调用handler获取 msg.obj.toString() 时，所得值显示为乱码；多次转换编码无果，后改变记事本的编码，成功！

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