Remove Element

Given an array and a value, remove all instances of that value in place and return the new length.

 

The order of elements can be changed. It doesn't matter what you leave beyond the new length.

#include<iostream>#include<algorithm>using namespace std;int main(){int a[] = { 1, 2, 3, 4, 5, 2, 2, 6, 7 };int len = sizeof(a) / sizeof(a[0]);int temp = 0;//for (int i = 0; i < len; i++)//{//if (a[i] != 2)//{//a[temp]=a[i];//temp++;//}//}int b[] = {NULL};int k = 0;for (int i = 0; i < len; i++){if (a[i] != 2)b[k++] = a[i];}for (int j = 0; j < k; j++){a[j] = b[j];}//数组中不是新的数组元素  带有旧的元素；for (int i = 0; i < k; i++)cout << a[i] << endl;system("pause");return 0;}