LeetCode 19. Remove Nth Node From End of List详解
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关于为什么需要添加一个头节点的解释。
ListNode *removeNthFromEnd(ListNode *head, int n) { if (head==NULL || n<=0){ return NULL; } ListNode preHead(0); preHead.next=head; head=&preHead; ListNode *p1, *p2; p1=p2=head; for(int i=0; i<n; i++){ if (p2==NULL) return NULL; p2=p2->next; } while (p2->next!=NULL){ p2=p2->next; p1=p1->next; } p1->next = p1->next->next; return head->next; }
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