使用org.apache.commons.io.FileUtils,IOUtils;工具类操作文件

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解决转换空格
String fileName = StringUtils.trim(file.getName());

String formatFileName = encodingFileName(name);//在后面定义方法encodingFileName(String fileName);
response.setHeader("Content-Disposition", "attachment; filename=" + formatFileName );

//处理文件名中出现的空格

//其中%20是空格在UTF-8下的编码

public static String encodingFileName(String fileName) {
        String returnFileName = "";
        try {
            returnFileName = URLEncoder.encode(fileName, "UTF-8");
            returnFileName = StringUtils.replace(returnFileName, "+", "%20");
            if (returnFileName.length() > 150) {
                returnFileName = new String(fileName.getBytes("GB2312"), "ISO8859-1");
                returnFileName = StringUtils.replace(returnFileName, " ", "%20");
            }
        } catch (UnsupportedEncodingException e) {
            e.printStackTrace();
            if (log.isWarnEnabled()) {
                log.info("Don't support this encoding ...");
            }
        }
        return returnFileName;

}

或者：

fileName = URLEncoder.encode(fileName, "utf-8")

fileName = fileName.Replace("+", "%20"); encode后替换解决空格问题

response.addHeader("Content-Disposition", "attachment;filename=" + fileName, "utf-8");

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