使用Apache HTTP发送POST/GET请求

来源：互联网发布：淘宝智能版多少钱编辑：程序博客网时间：2024/06/05 20:30

POST请求

方法一，直接传入Instream

public static String post(String url, InputStream instream){        try {        //该Request是org.apache.http.client.fluent.Request;            HttpEntity entity = Request.Post(url)                    .bodyStream(instream,ContentType.create("text/html", "UTF-8"))                    .execute().returnResponse().getEntity();            return entity != null ? EntityUtils.toString(entity) : null;        } catch (Exception e) {            logger.error("post请求异常，" + e.getMessage() + "\n post url:" + url);            e.printStackTrace();        }        return null;    }

方法二，传入普通json字符串

private static String httpPost(String url, String data) {        try {            HttpEntity entity = Request.Post(url)                    .bodyString(data,ContentType.create("text/html", "UTF_8"))                    .execute().returnResponse().getEntity();            return entity != null ? EntityUtils.toString(entity) : null;        } catch (Exception e) {            logger.error("post请求异常，" + e.getMessage() + "\n post url:" + url);            e.printStackTrace();        }        return null;    }

GET请求

private static String httpGet(String url) {        try {            HttpEntity entity = Request.Get(url).                    execute().returnResponse().getEntity();            return entity != null ? EntityUtils.toString(entity) : null;        } catch (Exception e) {            logger.error("get请求异常，" + e.getMessage() + "\n get url:" + url);            e.printStackTrace();        }        return null;    }

文件上传

public static String postFile(String url,String name,File file){        try {            HttpEntity reqEntity = MultipartEntityBuilder.create().addBinaryBody(name, file).build();            Request request = Request.Post(url);            request.body(reqEntity);            HttpEntity resEntity = request.execute().returnResponse().getEntity();            return resEntity != null ? EntityUtils.toString(resEntity) : null;        } catch (Exception e) {            logger.error("postFile请求异常，" + e.getMessage() + "\n post url:" + url);            e.printStackTrace();        }        return null;    }

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